Find the number of coins of 1.5 cm diameter and 0.2 cm thickness to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.
Answers
Answered by
1
Given,
radius of coin = 1.5/2 cm
radius of right cylinder = 4.5/2 cm
height of coin = 0.2 cm
height of cylinder = 10 cm
...no of coins required = vol of right cylinder/vol of each coin
= pi*r*r*h/pi*r*r*h
pi gets cancelled
=r*r*h/r*r*h
=(4.5/2)2* 10/ (1.5/2)2* 0.2
= 20.25/4* 10/ 2.25/ 4* 0.2
4 gets cancelled
=20.25*10/2.25*02
= 202.5/0.45
= 450
so, 450 coins are required
Answered by
6
Answer:
2 Volume of one coin = T x (1.5) x 0.2
Volume of cylinder= Tx (4.5) x
So number of coins to be melted
=volume of cylinder/volume of each coin
=4.5/1.5 x 10/0.2
= 9 x 50
= 450
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