find the number of coins of 1.5 cm diameter and 0.2cm thickness to be melted to form a right circular cyclinder of hieght 10 cm and diameter 4.5 cm .
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Each one of those coins is also a cylinder (just a very very short one), and its volume is
V = πr²h = π(.75)²(.2) = 9π/80 cm³
The right circular cylinder has volume V = π(2.25)²(10) = 405π/8 cm³.
Divide the larger cylinder's volume by the volume of each coin = (405π/8) / (9π/80) = 450 coins .
Hope it helps.
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V = πr²h = π(.75)²(.2) = 9π/80 cm³
The right circular cylinder has volume V = π(2.25)²(10) = 405π/8 cm³.
Divide the larger cylinder's volume by the volume of each coin = (405π/8) / (9π/80) = 450 coins .
Hope it helps.
Please mark it as brainliest.
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Radius of coin=1.5/2=3/4cm
height of coin=0.2=1/5cm
volume of coin=22/7 *r^2 *h
=22/7*3/4*3/4*1/5=0.353cm^3
Radius of cylinder=4.5/2=9/4cm
Height of cylinder=10cm
Volume of cylinder=22/7*r^2*h
=22/7*9/4*9/4*10=159.107cm^3
no. of coins=159.107/0.353=450
height of coin=0.2=1/5cm
volume of coin=22/7 *r^2 *h
=22/7*3/4*3/4*1/5=0.353cm^3
Radius of cylinder=4.5/2=9/4cm
Height of cylinder=10cm
Volume of cylinder=22/7*r^2*h
=22/7*9/4*9/4*10=159.107cm^3
no. of coins=159.107/0.353=450
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