find the number of diagonals and sum of the exterior angels of hexagon
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1) HERE
THE FORMULA To FIND NO. OF DIAGONAL IN Polygon =n(n-3) /2 (n=no. of side)
so in a hexagon their are 6 side
NOW
6(6-3)/2=9
2) sum of all exterior angles of any polygon is 360 degree
please mark me as brainliest
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