Math, asked by arotihembram, 1 year ago

if tejinder walks at 5.4 km/h from his house, he is 9 minutes late for school. starting off at the same time, if he cycles to school at 12 km/h, he reaches 5 minutes 40 seconds early. how far is tenjinder's school form his house. (Answer in unitary method )​

Answers

Answered by amitnrw
20

Answer:

D = 2.4 km

Step-by-step explanation:

Let say Distance of School  = D km

& Time to reach scool at time = T hr

tejinder walks at 5.4 km/h from his house,

Time taken  = D/5.4  hr

9 min late = 9/60 hr

=> D/5.4 = T + 9/60

=> 10D/54 = T + 9/60

=> 5D/27 - 9/60 = T

tejinder cycles at 12 km/h from his house,

Time taken  = D/12  hr

5 minutes 40 seconds early = 340 secs = 340/3600 hr = 17/180 hr

=> D/12 = T - 17/180

=> D/12 + 17/180 = T

5D/27 - 9/60  = D/12 + 17/180

Multiplying by 540 both sides

=> 100D - 81 = 45D + 51

=> 55D = 132

=> 5D = 12 km

=> D = 12/5 km

=>D = 2.4 km

School is 2.4 km away

Answered by kahan3591
0

Answer:

2.4 km is the final answer

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