if tejinder walks at 5.4 km/h from his house, he is 9 minutes late for school. starting off at the same time, if he cycles to school at 12 km/h, he reaches 5 minutes 40 seconds early. how far is tenjinder's school form his house. (Answer in unitary method )
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Answered by
20
Answer:
D = 2.4 km
Step-by-step explanation:
Let say Distance of School = D km
& Time to reach scool at time = T hr
tejinder walks at 5.4 km/h from his house,
Time taken = D/5.4 hr
9 min late = 9/60 hr
=> D/5.4 = T + 9/60
=> 10D/54 = T + 9/60
=> 5D/27 - 9/60 = T
tejinder cycles at 12 km/h from his house,
Time taken = D/12 hr
5 minutes 40 seconds early = 340 secs = 340/3600 hr = 17/180 hr
=> D/12 = T - 17/180
=> D/12 + 17/180 = T
5D/27 - 9/60 = D/12 + 17/180
Multiplying by 540 both sides
=> 100D - 81 = 45D + 51
=> 55D = 132
=> 5D = 12 km
=> D = 12/5 km
=>D = 2.4 km
School is 2.4 km away
Answered by
0
Answer:
2.4 km is the final answer
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