Math, asked by guthikondakovipcr9zl, 11 months ago

Find the number of digits 2^2018 if log10 2=0.3010

Answers

Answered by dicki

0

fulcrum tak ami do is ek u cm Uckfield

Answered by anujgarg148

1

Answer:

608

Step-by-step explanation:

log{2^2018} base 10

=2018 (0.3010)

=607.4...

therefore no. of digits = 607+1

=608

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