Question

Find the number of digits in 810, given that log 2 = 0.301

Answer 1

Answer:

10

Step-by-step explanation:

8^10 = 2^30

30*0.301 = 9.03

Hence number of digits = Integral part of (9.03) + 1 = 9+1 = 10

Answer 2

The number of digits in $8^{10}$ is 10

Step-by-step explanation:

Let us first find the value of $8^{10}$

To find the value of $8^{10}$ we need to take log.

There fore we get, log($8^{10}$)

By log theorem, the power comes in front

therefore log($8^{10}$) = 10 log(8)

now 8 can be written as $2^{3}$

therefore log($2^{3}$) similarly by log theorem we can write as 3log(2)

therefore now we get,

30 log(2)

According to the question we get, log 2= 0.301

therefore, 30 log 2 = 9. 03

Thus total number of digits are 10