Math, asked by maahayatep, 1 year ago

Find the number of digits in the square root of each of the following numbers (without any calculation)? 64 144 4489 27225 390625

Answers

Answered by SraheelaA
39
√64 = 8
√144 = 12
√4488 = 69
√27225 = 165
√390625 = 625
Answered by wachimsiddique33
1

Answer:

(i) Here, 64 contains two digits which is even.

Therefore, number of digits in square root =

2

n

=  

2

2

=1

(ii) Here, 144 contains three digits which is odd.

Therefore, number of digits in square root = \

2

n+1

=  

2

3+1

=  

2

4

=2

(iii) Here, 4489 contains four digits which is even.

Therefore, number of digits in square root = \

2

n

=  

2

4

=2

(iv) Here, 27225 contains five digits which is odd.

Therefore, number of digits in square root = \

2

n

=  

2

5+1

=3

(v) Here, 390625 contains six digits which is even.

Therefore, number of digits in square root = \

2

n

=  

2

6

=3

Step-by-step explanation:

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