if A and B are two complementry angles then prove that sin*2A+sin*2B =1
ansss:
is that sin square A?
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sin*2A+sin*2B=sin*2A+1-cos*2B=1+sin*2A -cos*2B=1+cos(A+B).cos(A-B)
=1+0.cos(A-B)=1
=1+0.cos(A-B)=1
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