what is the external net force exerted on a 3.5 kg papaya, which is being pushed across a table and has an acceleration of 2.2 m/s to the left?
Answers
Answered by
36
Answer:
7.7 N
Explanation:
formula to find the force is
F = mass × acceleration
so
F = 3.5 × 2.2
F = 7.7 Newton
(I'm not sure but by this formula you'll get this answer )
Similar questions