find the number of electron present in 16C of charge
Answers
Answered by
1
Answer:
since q=ne
n=q/e=16/1.6×20^-19=10^1+10^19=10^20
Answered by
0
Answer:
1560c
Step-by-step explanation:
1/1.6022 x 10^-19 c (2.5x10^-16)
1.560x10^3 c
=1560 c
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