Question

find the number of electron present in 16C of charge​

Answer 1

Answer:

since q=ne

n=q/e=16/1.6×20^-19=10^1+10^19=10^20

Answer 2

Answer:

1560c

Step-by-step explanation:

   1/1.6022 x 10^-19 c (2.5x10^-16)

    1.560x10^3 c

     =1560 c