Question

Find the number of electrons passing through the conductor if the charge is 0.8 C​

Answer 1

Given:

Charge on conductor (Q) = 0.8 C

To Find:

Number of electrons passing through the conductor (n)

Answer:

Quantization of charge: Electric charge is always an integral multiple of charge on electron (e).

$\bf \implies Q = ne \\ \\ \rm \implies 0.8 = n \times 1.6 \times {10}^{ - 19} \\ \\ \rm \implies n = \dfrac{0.8}{1.6 \times {10}^{ - 19} } \\ \\ \rm \implies n = 0.5 \times {10}^{19} \: electrons$

$\therefore$ $\boxed{\mathfrak{Number \ of \ electrons \ passing \ through \ the \ conductor \ (n) = 0.5 \times 10^{19} \ electrons}}$

Answer 2

$\sf Electrons \: in \: 1C \: of \: charge = \red{6.25 \times {10}^{18}}$

$→ \sf 1C = 6.25 \times {10}^{18} electrons$

　　　　　　　　　　　　　　　　　　　　　　　　　　　

$\sf Electrons \: in \: 0.8C \: of \: charge = \red{0.8 \times 6.25 \times {10}^{18}}$

$→\sf 0.8C = 0.8 \times 6.25 \times {10}^{18} \: electrons$

$\sf 0.8 = 5 \times {10}^{18} electrons$

　　　　　　　　　　　　　　　　　　　

$\therefore \: \underline{\underline{\purple {\sf {0.8 = 5 \times {10}^{18} electrons}}}}$