Question

if a+b+c = 6, ab+ bc+ ca = 2(a+b+c) find a² + b² + c²​

Answer 1

Answer:

The answer is a -4

Step-by-step explanation:

a+b+c=6 and ab+bc+ca=11

Let a =3

b=1 and

c=2

Now, putting the values in the given equations.

a+b+c=6 and ab+bc+ca=11

3+1+2=6 and 3*1+1*2+3*2=11

3+2+6=11. 11=11

Now, put the values in the equation we have to find that is

a^2+b^2+c^c-3abc

3^2+1^2+2^2–3*3*1*2

9+1+4–18

14–18

-4.

Hence, the answer is -4..

Answer 2

Answer:

36 - 24 = 12

Step-by-step explanation:

as a +b +c = 6

so (a +b+c )² = 36

= a² +b² + c² + 2 (ab + ca + bc ) = 36

so a²+ b² + c² + 2* (2 (a+b+c) ) = 36

so a²+ b²+c² = 36- 24 =12