Find the number of g atoms and weight of an element having 2 x 102 atoms. Atomic mass of element is 32.
(A) 0.22g atom, 9.2 g
(B) 0.22g atom, 8.2 g
(C)0.33g atom, 10.6 g
(D) 0.33g atom, 9.6g
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Answer:
(C) 0.33g atom, 10.6 g
Explanation:
1 mole = 6.023 × 10^23
Therefore, Atom = 1/ 6.023×10^23
2 × 10^23 atom = 2×10^23 / 6.023×10^23
2 × 10^23 atom = 0.33 mol
Therefore element given is = 0.33 g of atom
6.023 × 10^23 = 32 g
Therefore, 2×10^23 atom = 32×2x10^23 / 6.023×10^23
2×10^23 atom = 10.627 g
And Hence, option (c) is correct.
0.33 g of atom and 10.6 g is weight of element.
By
Aaditya Singh
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