Question

Find the number of GAM in the each substance given below a)20 g hydrogen atom b)71 g chlorine atom c)64 g oxygen atom d)42 g nitrogen atom​

Answer 1

Explanation:

Molecular weight of oxygen is 32.

Thus the number of moles present in 16 g of O

2

will be 0.5

Number of molecules present will be 0.5N

A

Number of gram atoms will be 0.5×2N

A

=N

A

( Since one molecule of oxygen contains 2 atoms of oxygen)

1 mol of a gas occupies 22.4l at STP, thus given sample will occupy 11.2l at STP.

No. of protons=No.of gram atoms×8=8N

A

(Since one oxygen atom contains 8 protons)