Question

find the number of GM's inserted between 1 and 64 when the ratio of 1st mean mean to the last mean is 1:16.
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Answer 1

Answer:

How many GMs are there between 1 and 64 when the ratio of the first and the last mean is 1:16?

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Let n be the number of GMs between 1 and 64 and r be the common ratio.

Then 64 is the (n+2)the term.

So. a×r^(n+1) = 64 where a is the first term which is 1.

So. r^(n+1) = 64……(1)

Also r^n/r = 16/1

=> r^ (n-1) =16. ……(2)

Dividing (1) by (2) we get

r^2 = 4 => r=2

Using this in (1) we get 2^(n+1) = 64= 2^6

So. n+1=6 => n=5

Step-by-step explanation:

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