Find the number of integers between 100 and 300 which are divisible by 7
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Answer:
the last number divisible by 7 between 100 and 300 is 294
Step-by-step explanation:
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we have to find sum of integers between 100 and 300 divisible by 7
Now,
if we see,
the first number between 100 and 300 divisible by 7 is 105
therefore,
next number will be (105+7) i.e. 112
and so on
and the last number divisible by 7 between 100 and 300 is 294.
So, it forms an A.P
105, 112, 119,..............,294
Now,
first term, a = 105
last term, l = 294
and,
common diffrence, d = 7
now,
294 = 105 + 7(n-1)
=> 7(n-1) = 294-105
=> n- 1 = 189/7
=> n = 27+1
=> n = 28
Therefore,
there are 28 terms in thus A.P
Now,
sum of all terms, S = n(a+l)/2
=> S= 28(105+294)/2
=> S = 14 × 399
=> S = 5586
HENCE,
sum of terms = 5586
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