Question

Find the number of molecules of an ideal gas in a volume of 1.000 cm3 at STP.

Answer 1

heres the answer hope it helps:)

Answer 2

The number of molecules of an ideal gas in a volume of 1.000 $\bold{cm^3}$ at STP is  $\bold{2.68 \times 10^{19}}$

Explanation:

Ideal volume of gas at STP ( Standard Temperature and Pressure ) = 22.4 L

Number of 22.4 litre molecules of ideal gas at STP = $6.022 \times 10^{23}$

Number of molecules in STP ( Standard Temperature and Pressure ) at $22.4 \times 10^3 cm^3$ of ideal gas  = $6.022 \times 10^{23}$

Now,

Number of molecules in ideal gas 1 $cm^3$ at STP (standard temperature and pressure )  

$=\frac{6.022 \times 10^{25}}{22.4 \times 10^{3}}$

$=\frac{6.022 \times 10^{20}}{22.4}$

$=0.268 \times 10^{20}$

$=2.68 \times 10^{19}$