Question

find the number of molecules or ions in which d orbitals are not used in hybridised pcl6-,pcl4-,if4-,xeO3f2,ICI2+,SF2,AsF4+,SiF4​

Answer 1

Answer:

In PCl

5

​

No, of e

−

pairs around central atom P=5

No of lone pairs =0 and hybridisation - sp

3

d Shape = trigonal bipyramidal. In PCl

4

+

​

−number. of e

−

pairs =4, lone pairs =0, hybridisation =sp

3

and shape−tetrahedral.

In PCl

6

−

​

− number of e

−

pairs =6, lone pairs =0,hybridisation=sp

3

d

2

and shape is octahedral.

Answer 2

Total 4 of the following molecules or ions don't have d-orbitals in their hybridization $P(Cl_{4})^{+}, ICl_{2}^{+}, SF_{2} and S$.

Explanation:

To find,

Molecules or ions in which d-orbitals are not used,

Let us get the hybridization of every molecule and ion first, the following are the hybridizations of molecules and ions.

Hybridization of $P(Cl_{6})^{-}$ = $sp^{3}d^{2}$

Hybridization of $P(Cl_{4})^{+}$ = $sp^{3}$

Hybridization of $IF_{4} ^{-}$ = $sp^{3}d$

Hybridization of $XeO_{3}F_{2}$ = $sp^{3}d$

Hybridization of $ICl_{2}^{+}$ = $sp^{3}$

Hybridization of $SF_{2}$ = $sp^{3}$

Hybridization of $AsF_{4}$ = $sp^{3}d$

Hybridization of S = sp.

From the above hybridization list we can get that $P(Cl_{4})^{+}, ICl_{2}^{+}, SF_{2} and S$ don't have d orbitals in there hybridization.