find the number of moles of carbon atoms in 540g of glucose(c6 h12 o6)?
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Answer:
no of atoms= atoms ×atomicity×avagadro number then 6×6.023×10^23
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Explanation:
mass of one mole of glucose = C6H1206 = (6×12.01+12×1.01+6×16.00)g = 180.18g
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