Question

find the number of moles of solute present in 500 ml of 2 m H2 so4 solution​

Answer 1

Explanation:

Normality=equivalentweight×volume(ml)1000

0.2=98/2ω×5001000

ω=4.9gm

Answer 2

We have,

v = 500 ml

Convert it to liters

So,

v= 500/1000

 = 0.5L

Now,

Molarity = Moles of solute / Volume of solution

But we have,

Molarity= 2m

Volume= 0.5L

So, Put those value in the formula,

Molarity = Moles of solute / Volume of solution

          2 = moles / 0.5

∴ Moles of H2SO4 = 2 * 0.5 = 1

So,

The number of moles of solute present in 500 ml of 2 m H2 so4 solution is 1