Find the number of multiple of 9 lying between 300 and 700.
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Here series will be = 306, 315, 324, 333,...........693
So we have the first term a = 306 and d = 9 and last term l = 693
693 = 306 + (n-1)9
77 = 34 + (n-1)
n = 77 - 34 +1
= 44
Sum = n/2(a+l)
= 44/2(306+693)
= 22(999)
= 21978.
Hope this helps!
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