Find the number of natural.number between101to999 which are divisible. By 2and5
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answer = 89( first number is divided by 2 and 5) difference= 10 an=990 (last number is to be divided by 2 and 5) an=a(n-1)d 990=110 +10n-10
880+10= 10n 890=10n n=89. therefore the number of natural number between 101 to 999 which are divided by 2 and 5 are 89
880+10= 10n 890=10n n=89. therefore the number of natural number between 101 to 999 which are divided by 2 and 5 are 89
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110,120,130,140,150,160,170,180,190,200,210,220,230,240,250,260,270,280,290,300,310,320,330,340,350,360,370,380,390,400,410,420,430,440,450,460,470,480,490,500,510,520,530,540,550,560,570,580,590,600,610,620,630,640,650,660,670,680,690,700,710,720,730,740,750,760,770,780,790,800,810,820,830,840,850,860,870,880,890,900,910,920,930,940,950,960,970,980,990,
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