Find the number of natural numbers between 95 and 985 which are divisible by 2 and 5 both
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Answer:
89 numbers
Step-by-step explanation:
A number is divisible by 2 If a number ends in a 0, 2, 4, 6 or 8. ( the digit in ones)
If a number ends in either a 0 or 5, it is divisible by 5.
For a number to be divisible by both 2 and 5 it must satisfy the above tests. Therefore it must end in 0 in the ones place.
From 95 to 985 we have
100, 110, 120, 130, 140, 150,160,170,180,190
200,...
.
.
.
900, 910,920,930,940,950,960,970,980
Their count is 10x8+9=89 numbers
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