Find the number of numbers between 1 and 100 both inclusive that are divisible by 3 or 5
Answers
Answer:
47
Step-by-step explanation:
SolutionThere are 20 numbers divisible by 5 between 1 and 100, and 33 numbers divisible by 3 between 1 and 100.
So there are 20 + 33 = 53, so 53 numbers divisible by one or the other, but this also includes every number which is divisible by both 5 and 3 twice.
Such numbers are 15, 30 and so on multiples of 15 between 1 to 100
There are 6 numbers divisible by 15 between 1 and 100 (i.e divisible by both 3 and 5)
So answer is 20+33-6 = 47
Question
Find the number of numbers between 1 and 100 both inclusive that are divisible by 3 or 5
Answer
Given:-
The number of numbers Which are both
Divisible by 3 and 5
To Find :-
The numbers which are divisible by 3 and 5
Solution of the question :-
To be divisible by 3 and 5 simultaneously, a number has to be divisible by
15 (3x5).
Between 1 and 100, there are
100/15=6.66 and so 6 numbers (you can check that by multiplying 15 by 6 and 7 which gives us 90 and 105 respectively)-15,30,45,60,75 and 90.