Find the number of numbers less than 2000 that can be formed using digits, 1,2,3,4 if repetition is allowed
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The first digit can't be 1 as number required is greater than 2000. So there are three possibilities 2,3,4. For second digit it can be 1 or remaining two digits. Hence three ways. Similarly third digit can be chosen in two ways and the last one is the one which is left.
Thus number of ways =3×3×2×1=18=3×3×2×1=18
With repetition:
The question is not clear so I'll assume four digit numbers greater than 2000. First digit can't be 1. So there are 3 ways. The rest of three digits can be any of 1,2,3,4.
Thus number of ways =3×4×4×4=192=3×4×4×4=192
Hope this helps
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