find the number of ordered pairs ( x , y ) of integers such that x² + y² no span pls
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Answered by
0
Answer:
please mark as brainliest and follow
Step-by-step explanation:
Hi,
x^2 + y^2 ≤ 5
ordered pairs (x,y) of integers satisfying this... would be any on or within the circle:
for Ex: (0,0) and those using ±1 or ±2
Answered by
1
Answer:
x
2
−y
2
=12345678(x,yϵ1
+
)
RHS is even, so, x & y should be odd integer but difference square of two odd integer is multiple of 8 but RHS is not multiple of 8
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