Question

find the number of oxygen and Aluminium ions in 1.02 gram of Aluminium oxide​

Answer 1

Answer:

Explanation:

1 mole of Al2O3 = Formula mass of Al2O3 in grams

= Mass of Al × 2 + Mass of O × 3

= 27 × 2 + 16 × 3

= 54 + 48

= 102 grams

Now, 1 mole of Al2O3 contains 2 moles of Al.

So, Mass of Al in 1 mole of Al2O3 = Mass of Al × 2

= 27 × 2

= 54 grams

Now, 102 g aluminum oxide contains = 54 g Al

So 0.051 g aluminum oxide contains = 54/ 102 × 0.051 g Al

= 0.027 g Al

The atomic mass of aluminium is given to be 27 u. This means that 1 mole of aluminium atoms ( or aluminium ions ) has mass of 27 grams , and it contains 6.022 × 10^23 aluminium ions.

Now, 27 g of aluminium has ions = 6.022 × 10^23 aluminium ions.

So, 0.027 g of aluminium has ions = 6.022 × 10^23 / 27 × 0.027.

= 6.022 × 10^20

Thus, the number of aluminium ions (Al³+) in 0.051 gram of aluminium oxide is 6.022 × 10^20.

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Answer 2

Answer:

Hi

The no. of oxygen is 6.022×10^20.

hope it helps..❤...