Chemistry, asked by vippandian1837, 1 year ago

Find the number of photons emitted per second by a 25 watt source of monochromatic light of wavelength  6000 \AA ?

Answers

Answered by phillipinestest
35

From the given,

Watt of bulb = 25 watt

Wavelength of light = 6000 { A }^{ 0 } = 600 nm

Power of the bulb = 25 watt

=\quad \frac { Work }{ time } \quad =\quad 25\quad J{ s }^{ -1 }

Energy of one photon = E = \frac { hc }{ \lambda }

=\quad \frac { 6.626\quad \times { 10 }^{ -34 }\quad Js\quad \times \quad 3.0\quad \times { 10 }^{ 8 }\quad m{ s }^{ -1 }\quad }{ 600\quad \times \quad { 10 }^{ -9 }m }

=\quad 3.313\quad \times { 10 }^{ -19 }\quad J

Number of photons emitted per second =\quad \frac { 100\quad { Js }^{ -1 } }{ 3.313\quad \times \quad { 10 }^{ -19 }J } \quad =\quad 3.018\quad \times \quad { 10 }^{ 20 }{ s }^{ -1 }

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