Question

Find the number of points in the locus represented by the equation x² + y² = 0​

Answer 1

Answer:

x2+y2=0

⇒x2=-y2

A perfect square can never be equal to the negative of another perfect square except at (0,0)

So the loci of the given eqaution is origin that is the point (0,0)

Answer 2

Answer:

Step-by-step explanation:

Given equation is  x² + y² = 0​

      ⇒  $x^{2} +y^{2} = 0$

            ⇒$x^{2} -y^{2}$

A perfect square can never be equal to the negative of another perfect square except at (0,0)

So the loci of the given eqaution is origin that is the point (0,0)

The project code is #SPJ3