Question

Find the number of possible line segments from five points such that no three points are collinear.​

Answer 1

Given :

Given no of points = 5

To Find :

No of possible line segments from these points such that no three points are  collinear = ?

Solution :

Here we have to select 2 points from the given 5 points and make  a line .

So on following the condition that no three points should be collinear , the no of such selections will be :

= $^5C_2$

=$\frac{5!}{2! \times (5-2)!}$

=$\frac{5 \times 4 \times3! }{2! \times 3!}$

=10

So , the no of possible line segments  from the 5 points with no three points collinear is 10 .

Answer 2

Answer:

answer is 10

Step-by-step explanation: