Question

Find the number of real roots of equation
(x - 1)2 + (x - 2)2 + (x - 3)2 = 0.​

Answer 1

Answer:

2x-2+2x-4+2x-6=0

6x-12=0

6x=12

x=2

Answer 2

Answer:

Given Equation is (x - 1)^2 + (x - 2)^2 + (x - 3)^2 = 0

= > x^2 + 1 - 2x + x^2 + 4 - 4x + x^2 + 9 - 6x = 0

= > 3x^2 - 12x + 14 = 0 .

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