find the number of sides in a regular polygon if its interior angle is equal to its exterior angle
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According to given sum,
let the number of sides of the regular polygon be n.
Then the interior angles of the polygon is (n-2)180/n
The exterior angle will be 360/n.
From the question,
Interior angle = exterior angle .
![= > \: \frac{(n - 2)180}{n} = \frac{360}{n} = > \: \frac{(n - 2)180}{n} = \frac{360}{n}](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%5C%3A++%5Cfrac%7B%28n+-+2%29180%7D%7Bn%7D++%3D++%5Cfrac%7B360%7D%7Bn%7D+)
=> (n-2)180=360
=> (n-2)=2
=> n= 4
so, the number of sides of the polygon will be 4 .
:-)Hope it helps u.
let the number of sides of the regular polygon be n.
Then the interior angles of the polygon is (n-2)180/n
The exterior angle will be 360/n.
From the question,
Interior angle = exterior angle .
=> (n-2)180=360
=> (n-2)=2
=> n= 4
so, the number of sides of the polygon will be 4 .
:-)Hope it helps u.
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