find the number of sides of a regular polygon if each of its interior angle is 108*
Bitti13:
IF EACH IS 108 OR TOTAL ITERIOR ANGLE IS 108??
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180(n−2)n=108°
180n−360=108n
72n=360
n=5
mark as brainliest please
180n−360=108n
72n=360
n=5
mark as brainliest please
Answered by
1
Answer:
if each interior angle is 108 then ,
each exterior angle is 180 -108 = 72
So, the no. of sides = 360
each exterior angle
= 360/72
= 5
Step-by-step explanation:
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