Find the number of sides of a regular polygon, if the exterior angle is one-ninth of its interior angle?
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let interior angle be x and exterior angle be y
so, x + y = 180°.............(1)
the exterior angle is one-ninth of its interior angle
so, y = x/9.............(2)
substitute (2) in (1)
x + x/9 = 180°
(9x + x)/9 = 180°
10x = 180° × 9
x = 18° × 9
x = 162°
so, interior angle is x = 162°
exterior angle is y = 180° - 162° = 18°
so, no of sides of polygon = 360°/18° = 20
no of sides of a polygon is 20
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