Physics, asked by stylishtamilachii001, 1 month ago

Find the number of significant figures for the following :

(i) 0.0087 (ii) 2.65 x 1024 m​

Answers

Answered by ankushrathour2004
1

Answer:

hi

good evening

how are you

Explanation:

Answer: 1 <br> The given quantity is

. <br> If the number is less than one, then all zeros on the right of the decimal point (but left to the first non-zero) are insignificant. This means that here, two zeros after the decimal are not significant. Hence, only 7 is a significant figure in this quantity. <br> Answer : 3 <br> The given quantity is

. <br> Here, the power of 10 is irrelevant for the determination of significant figures. Hence, all digits i.e., 2, 6 and 4 are significant figures. <br> (c) Answer : 4 <br> The given quantity is

.<br> For a number with decimals, the trailing zeroes are significant. Hence, besides digits 2, 3 and 7, 0 that appears after the decimal point is also a significant figure. <br> (d) Answer: 4 The given quantity is 6.320 J. For a number with decimals, the trailing zeroes are significant. Hence, all four digits appearing in the given quantity are significant figures. (e) Answer: 4 The given quantity is 6.032 N

. All zeroes between two non-zero digits are always significant. (f) Answer: 4 The given quantity is 0.0006032

. If the number is less than one, then the zeroes on the right of the decimal point (but left to the first non-zero) are insignificant. Hence, all three zeroes appearing before 6 are not significant figures. All zeros between two non-zero digits are always significant. Hence, the remaining four digits are significant figures.

Answered by pattukonam
0

hai. can you please give me ur intro?

naa Kavi Varneka studying class 10 from Dharmapuri

Similar questions