train takes 20minutes to cover a distance of 19km. The ratio of the speeds of this train and another train is 3:4. How much time will the second train take to cover the same distance of 19km?
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Let original speed =xkm/hr
⇒ Time taken to travel = x90 hr
⇒ New speed =(x+15)km/hr
⇒ Time taken to travel = x+1590 hr
∴ x90 = x+1590 + 21
⇒ x90 − x+1590 = 21
⇒ 90( x1 − x+151 )= 21
⇒ x(x+15)
x+15−x = 1801
⇒ 15×180=x(x+15)
⇒ 2700=x 2 +15x
⇒ x 2 +15x−2700=0
⇒ x 2
+60x−45x−2700=0
⇒ x(x+60)−45(x+60)=0
⇒ (x+60)(x−45)=0
Speed can not be negative.
∴ The original speed of the train is 45km/hr
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