Question

. Find the number of solutions of the following pair of linear equations:

x+2y-8-0

2x +3y= 16​

Answer 1

Step-by-step explanation:

1. here
2. x+2y-8=0
3. x+2y =8 eq 1
4. 2x + 3y = 16 eq 2
5. eq 1 * 2 - eq 2
6. we get
7. 2x + 4y = 16 - 2x + 3y = 16
8. from here
9. y = 0
10. put y in eq 1
11. x + 2*0=8
12. x + 0=8
13. x =8