Question

Find the number of sqaure tiles of size 15 cm required for covering the floor of a room 9 m long and 6 m wide.Find also the cost of the tiles required if one tile costs 4.50​

Answer 1

It required 24 tiles and it costed rupees 108

Answer 2

Answer:



2400 tiles



Rs 10800




Step-by-step explanation:




Area of floor = length * width

Area of floor = 9 * 6 = 54 m^2

Area of a tile = 15 cm * 15cm

= (15/100) m * (15/100) m

= 225/10000 m^2

Number of tile required to cover floor = floor area / tile area

Number of tile required to cover floor = 54 / (225/10000)

= 540000/225

= 2400 tiles

Cost of one tile = Rs 4.5

cost of 2400 Tiles = 2400 * 4.5
= Rs 10800