find the number of square tiles of side 8 cm required to cover a wall 10 metre by 6 metre
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Answer:
Length of the wall = 10m
Breadth of the wall = 6m
Area = L × B = 60m^2
Now,
Side of squared tile = 8 cm or, 8/100 m = 0.008 m
so, area of tile = 0.0064 m^2
Now,
no. of tiles = area of wall / area of tile
So, no. of tiles = 60/0.0064
or, 60/64/10000 = (60 × 10000)/64
No. of tiles = 9375 tiles
Hope you understood :)
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