Question

Find the number of square tiles of size 15 CM required for covering the floor of a room 9 m long and 6 m wide. Find the cost of tiles required if one tiles cost rs 4.50

Answer 1

Answer:

Given, Length of room =4.5m and breadth of room =4 m

So, Area of room =4.5×4=18 m

2

Area of room =18×(10000 cm

2

)=180000cm

2

Size of tiles =(15 cm×10 cm)

So, Area of tile one =15×10=150 cm

2

So, number of tiles required to cover the floor=

Area of one tile

Area of floor

=

150

180000

=1200

It is given that for one tile it costs Rs. 4.50

Therefore. cost of covering the floor with tiles

=4.50×1200=Rs.5400

Answer 2

• the area of square tile: (0.15×0.15)m^2 :0.0225m^2
• the area of square tile: (0.15×0.15)m^2 :0.0225m^2the area of floor of room: (9×6)m^2 :

the area of square tile: (0.15×0.15)m^2 :0.0225m^2the area of floor of room: (9×6)m^2 : 54m^2

• the area of square tile: (0.15×0.15)m^2 :0.0225m^2the area of floor of room: (9×6)m^2 : 54m^2the total no. of tiles: 54÷0.0225: 2400 tiles
• the area of square tile: (0.15×0.15)m^2 :0.0225m^2the area of floor of room: (9×6)m^2 : 54m^2the total no. of tiles: 54÷0.0225: 2400 tilesthe cost of tiles: ₹(2400×4.50): ₹10,800
• the answer is ₹10,800.