find the number of terms in an A.P.5,9,13,17,...105
Answers
Answered by
2
Given terms
5,9,13,17..105
we have
first term (a) = 5
and common difference (d) = 9-5 =4
let an = 105
a + (n-1) d = 105
5 +( n-1) 4= 105
5 + 4n - 4 = 105
4n + 1 = 105
4n = 104
n = 26
terms of terms in given Ap = 26
Answered by
3
26
Step-by-step explanation:
an=a+(n-1)d
105=5+(n-1)4
n-1=25
n=26
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