Question

find the number of terms in an A.P.5,9,13,17,...105​

Answer 1

Given terms

5,9,13,17..105

we have

first term (a) = 5

and common difference (d) = 9-5 =4

let an = 105

a + (n-1) d = 105

5 +( n-1) 4= 105

5 + 4n - 4 = 105

4n + 1 = 105

4n = 104

$n = \frac{104}{4}$

n = 26

terms of terms in given Ap = 26

Answer 2

26

Step-by-step explanation:

an=a+(n-1)d

105=5+(n-1)4

n-1=25

n=26

Mark as BRAINLIEST...