Question

If it is Given X = { x:x is a natural number and multiple of 3} and Y={ x:x is a natural number less than 6} then Find X U Y
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Answer 1

Solution :

Given,

X = {x:x is a natural number and multiple of 3}

= {3, 6, 9, 12, 15, ....}

Y = {x:x is a natural number less than 6}

= {1, 2, 3, 4, 5}

X ∪ Y = {3, 6, 9, 12, 15, ....} ∪ {1, 2, 3, 4, 5}

= { 1, 2, 3, 4, 5, 6, 9, 12, 15, 18, ...}

Explanation :

Union of sets(denoted by ∪) is combining two sets and writing their elements in a single set.

Intersection of sets(denoted by $\cap$) is the common elements of any sets A and B.

Answer 2

GIVEN :

X = { x:x is a natural number and multiple of 3}

Y={ x:x is a natural number less than 6}

TO FIND :

X U Y

SOLUTION :

It is given that X = { x:x is a natural number and multiple of 3}

Numbers which are natural number and multiple of 3 are as follows :-

3,6,9,12 ,15,18,21,24,27,30,33,36.........

Therefore :-

X = { 3,6,9,12 ,15,18,21,24,27,30,33,36.........}

Now , Y={ x:x is a natural number less than 6}

Natural number less than 6 are as follows :-

1,2,3,4,5

Y={ 1,2,3,4,5 }

X U Y = {1,2,3,4,5,6,9,12, 15,18,21,24,27,30,33,36.........}

ANSWER :

{1,2,3,4,5,6,9,12, 15,18,21,24,27,30,33,36.........}

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CONCEPT USED :-

Union of set :-

The union of two sets 1 and 2 is defined as the set of all the elements which lie in set 1 and set 2 or both the elements in 1 and 2 altogether.

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