Question

Find the number of terms in an AP whose first term is -14 and fifth term is 2 and sum of the terms is 40.​

Answer 1

Answer:

n=10  or -2

s0 consider n=10

Step-by-step explanation:

a=-14

a+4d=2

sn=40

4d=2+14=16

d=4

sn=n/2(2*a+(n-1)d)

40=n/2(2*a+(n-1)4)