Find the number of terms in AP 8, 12, 16, ……….. 124.
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The sum of last ten terms of the AP: 8,10,12,...,126 is same as the sum of first ten terms of the AP: 126,124,122,...,8.
Therefore, a=126,d=−2 and n=10.
Now, S
10
=
2
10
[2×126+(10−1)×−2]
⇒S
10
=5×[252−18]=1170
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