find the number of terms in arithmetic progression 100,96,92 _ _ _ _ 12
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a=100
an=12
d=-4
a=an-(n-1)d
100=12+4n-4
100=8+4n
4n=92
n=23
no. of terms are '23'
an=12
d=-4
a=an-(n-1)d
100=12+4n-4
100=8+4n
4n=92
n=23
no. of terms are '23'
Rithuram:
the formula is an=a+(n-1) d
but it is in decreasing order
did u get
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