find the number of terms in each of the following A.p 7,13,19,............205
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Answered by
6
a+(n-1)d=205
7+(n-1)6=205
(n-1)6=205-7
n-1)6=198
(n-1)=198/6
n=33+1
n=34
7+(n-1)6=205
(n-1)6=205-7
n-1)6=198
(n-1)=198/6
n=33+1
n=34
Answered by
2
Heya..!!
The first term , a = 7
Common Difference , d = a2 - a1
d = 13 - 7
d = 6
an = 205
an = a + (n-1)d
a + (n-1) d = 205
7 + (n-1) 6 = 205
(n-1) 6 = 205 - 7
(n-1) = 198 / 6
n-1 = 33
n = 33 + 1
n = 34
Hence ,
the number of term in this AP is 34.
HOPE IT MAY HELP YOU
☺️☺️
The first term , a = 7
Common Difference , d = a2 - a1
d = 13 - 7
d = 6
an = 205
an = a + (n-1)d
a + (n-1) d = 205
7 + (n-1) 6 = 205
(n-1) 6 = 205 - 7
(n-1) = 198 / 6
n-1 = 33
n = 33 + 1
n = 34
Hence ,
the number of term in this AP is 34.
HOPE IT MAY HELP YOU
☺️☺️
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