find the number of terms in each of the following aps 1,3,5.....31
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a=1. d= 2
Let
Tn= 31
a + (n-1).d = 31
1 + (n-1).2 = 31
(n-1).2 = 30
n-1 = 15
n = 16
Since 31 is the 16th term
Implies there are 16 terms in the series
Let
Tn= 31
a + (n-1).d = 31
1 + (n-1).2 = 31
(n-1).2 = 30
n-1 = 15
n = 16
Since 31 is the 16th term
Implies there are 16 terms in the series
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