Question

Find the number of terms in each of the following APs :
(1) 7,13,19,..., 205
(i) 18, 15., 13,...,-47​

Answer 1

Answer:

1)34

2)

Explanation:

Given sequence is 7,13,19,...,205

The first term a=7 and

the common difference d=13−7=6

the last term is 205

Let the last term be the n  

term

Therefore, a+(n−1)d=205

⟹7+(n−1)×(6)=205

⟹7−6+6n=205

⟹1+6n=205

⟹6n=205−1

⟹n=  6

204

⟹n=34

Therefore, the number of terms in the given sequence is 34