Math, asked by rajbhumihar, 1 year ago

find the number of terms in each of the following Aps (1) 7,13,19,....,205

Answers

Answered by Hacker291103
2
the answer is 34 you can use formula a+(n-1)d
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rajbhumihar: firts of all you subtract 7from205 and then dived 6from198 and then add 1
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Answered by Anonymous
0

\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}

 =  >n =  34

\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}

How many term are these in the AP 7,13,19,...........205?

\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}

Given sequence is 7,13,19,...,205

Given sequence is 7,13,19,...,205The first term a=7 and

The common difference d=13−7=6

The last term is 205

Let the last term be the nth term.

We know that the nth term of the arithmetic progression is given by -

 =  > a+(n−1)d

 =  > a+(n−1)d=205

 =  &gt; 7+(n−1)×(6)=205</p><p></p><p>

 =  &gt; 7− \: 6+6n=205</p><p></p><p>

 =  &gt; 1+6n=205</p><p></p><p>

 =  &gt; 6n=205−1

 =  &gt; 6n = 204

 =  &gt;n =   \frac{204}{6}

 =  &gt; n = 34

\sf\underline{\underline{\green{THEREFORE, \: }}}

The number of terms in the given sequence is 34

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