Find the number of terms in following :
( 2x 3y )19( 1 x2 2x )10
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Answered by
3
☆☞ Here is ur answer ☜☆
☆☞ The number of terms in the expansion of (a + b)n is n + 1.
So, number of terms in the expansion of (2x + 3y)19 = 19 + 1 = 20
(1 + x2 + 2x)20 = [(1 + x)2]20 = (1 + x)40
So, number of terms in expansion of (1 + x2 + 2x)20 = Number of terms in expansion of (1 + x)40 = 40 + 1 = 41
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Answered by
3
Heya.....
See here for your answer....
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The no of term in given series is...
( a+b )n is n+1
So,, (2x+3y)19 = 19+1 = 20
( 1+x2+2x) 20 = [(1+x)2]=20=(1+x)40
Now,,,
(1+x2+2x)20= no of terms
(1+x)40 = 40+1 = 41 ans...
-- Be Brainly....
See here for your answer....
=============
The no of term in given series is...
( a+b )n is n+1
So,, (2x+3y)19 = 19+1 = 20
( 1+x2+2x) 20 = [(1+x)2]=20=(1+x)40
Now,,,
(1+x2+2x)20= no of terms
(1+x)40 = 40+1 = 41 ans...
-- Be Brainly....
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